Question

At STP, how many moles of helium gas would occupy 60 L?

Answer 1

At STP (standard temperature and pressure), one mole of any gas occupies 22.4 liters. Therefore, to determine the number of moles of helium gas that would occupy 60 L at STP, we can use the following conversion factor:

1 mole He gas = 22.4 L He gas at STP

So, we can set up the following proportion:

x moles He gas / 60 L He gas = 1 mole He gas / 22.4 L He gas

where x is the number of moles of helium gas we want to find.

To solve for x, we can cross-multiply and simplify:

x moles He gas = (60 L He gas)(1 mole He gas / 22.4 L He gas)

x moles He gas = 2.68 moles He gas (rounded to two decimal places)

Therefore, 2.68 moles of helium gas would occupy 60 L at STP.