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What is the mass of a sample of N2 gas, which has a pressure of 3 atm, at a temperature of 50 °C, in a volume of 0.6 L?

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Step-by-step explanation:

We can use the ideal gas law to calculate the mass of the N2 gas sample:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant (0.08206 L·atm/mol·K), and T is the temperature.

First, we need to convert the temperature to Kelvin:

T = 50 °C + 273.15 = 323.15 K

Now we can rearrange the ideal gas law to solve for the number of moles:

n = PV/RT

n = (3 atm)(0.6 L)/(0.08206 L·atm/mol·K)(323.15 K)

n = 0.0705 mol

The molar mass of N2 is 28.02 g/mol, so we can calculate the mass of the N2 gas sample:

mass = n × molar mass

mass = 0.0705 mol × 28.02 g/mol

mass = 1.98 g

Therefore, the mass of the N2 gas sample is approximately 1.98 g.

User Ruslan Korkin
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