Question

Find the equation in standard form for the circle whose diameter has an endpoint at (-3, -4) and the origin.

4 x 2 + 4 y 2 - 12 x + 16 y = 0
4 x 2 + 4 y 2 + 12 x - 16 y = 0
4 x 2 + 4 y 2 - 12 x - 16 y = 0
4 x 2 + 4 y 2 + 12 x + 16 y = 0

Answer 1

The answer is option A.

`4 x 2 + 4 y 2 - 12 x + 16 y = 0`