Answer:
The given line has a slope of -3/2, since it is in the form y = mx + b, where m is the slope. Any line that is parallel to this line will also have a slope of -3/2.
To find the equation of the line that passes through the point (-2,3) and has a slope of -3/2, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where (x1, y1) is the given point and m is the slope. Substituting in the values we have:
y - 3 = (-3/2)(x - (-2))
y - 3 = (-3/2)x - 3
y = (-3/2)x - 3 + 3
y = (-3/2)x
Therefore, the equation of the line that is parallel to y = -3/2x - 8 and passes through the point (-2,3) is y = (-3/2)x.
Note that this line does not have a y-intercept, since it passes through the point (-2,3) and has a slope of -3/2.