Question

Carbon tetrachloride (CCI4) was prepared by reacting 125 g of carbon disulfide and 125 g of chlorine. Calculate the percent yield if 60.4 g of CCI4 were obtained from the reaction CS2 + 3 Cl2 ➡️CCI4 + S2Cl2

Answer 1

The balanced chemical equation for the reaction is:

CS2 + 3 Cl2 ➡️ CCl4 + S2Cl2

According to the equation, one mole of CS2 reacts with three moles of Cl2 to produce one mole of CCl4. The molar mass of CS2 is 76.14 g/mol, and the molar mass of CCl4 is 153.82 g/mol.

Theoretical yield of CCl4:

125 g CS2 × (1 mol CS2/76.14 g) × (1 mol CCl4/1 mol CS2) × (153.82 g CCl4/1 mol CCl4) = 318.3 g CCl4

This means that 318.3 g of CCl4 should have been produced according to the balanced equation.

Actual yield of CCl4 = 60.4 g

Percent yield = (actual yield / theoretical yield) × 100%

Percent yield = (60.4 g / 318.3 g) × 100%

Percent yield = 19%

Therefore, the percent yield of CCl4 is 19%.