Question

How many moles of NaOH are contained in a 65.0 mL of a 2.20 M solution of NaOH?

Answer 1

there are 0.143 moles of NaOH in 65.0 mL of a 2.20 M solution of NaOH.

Step-by-step explanation:

To calculate the number of moles of NaOH in a given solution, we need to use the formula:

moles = concentration (in M) x volume (in L)

We are given the concentration of NaOH solution as 2.20 M and the volume as 65.0 mL. However, we need to convert the volume to liters before we can use the formula.

65.0 mL = 65.0/1000 L = 0.065 L

Now we can plug in the values in the formula:

moles = 2.20 M x 0.065 L

moles = 0.143 moles

Therefore, there are 0.143 moles of NaOH in 65.0 mL of a 2.20 M solution of NaOH.

Answer 2

Answer:.143 moles

Explanation:

Step-by-step explanation:

We're going to use this equation

n

=

M

⋅

V

M meaning our molarity, n meaning our moles involved, and v meaning our volume in Liters.

n

=

2.20

⋅

.065

n=.143 moles.