Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 12 N acts on a certain object, the acceleration

of the object is 4 m/s². If the acceleration of the object becomes 10 m/s², what is the force?
ON

Answer 1

Answer:
`F=30N`

Explanation:

1. You know that the force acting on the object varies directly with the object's acceleration. Then, by definition, you have:

`F=ka`

Where
`F` is the force acting on the object,
`a` is the object's acceleration and
`k` is the constant of proportionality.

2. Keeping this on mind, you can calculate the constant of proportionality by substituting
`F=12` and
`a=4` into the equation and solving for
`k`:

`12=k4`

`k=(12)/(4)`

`k=3`

3. Now, you can calculate the force when the acceleration of the object becomes 10 m/s², as following:

`F=3(10)`

`F=30`

3. The result is:

`F=30N`