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(3х2^y- 2 -7*2^y-2)÷( 5*2^y-2)


1 Answer

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To simplify this expression, we can follow the order of operations:

1. Simplify the expression inside the parentheses first:

(3x2^y - 2 - 7x2^(y-2))

2. Combine like terms:

3x2^y - 7x2^(y-2) - 2

3. Rewrite the denominator with a common base of 2:

5x2^(y-2)

4. Divide the numerator by the denominator:

(3x2^y - 7x2^(y-2) - 2) ÷ (5x2^(y-2))

5. Simplify by dividing each term in the numerator by 5x2^(y-2):

(3x2^y)/(5x2^(y-2)) - (7x2^(y-2))/(5x2^(y-2)) - (2/(5x2^(y-2)))

6. Simplify the exponents:

(3/5)x^(y-2) - (7/5) - (2/5)x^(-2)

So the final simplified expression is:

(3/5)x^(y-2) - (7/5) - (2/5)x^(-2)

User Diego Saa
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