Question

What is the [NaNO3] (in mole/liter) of a solution made by mixing 2.00 grams of solid sodium nitrate with enough water to make a total volume of 50.0 mL?

Answer 1

the concentration of sodium nitrate in the solution is 0.470 M.

Step-by-step explanation:

To calculate the concentration of sodium nitrate in the solution, we need to first convert the mass of solid sodium nitrate to moles. We can do this using the molar mass of NaNO3, which is 85.0 g/mol:

moles NaNO3 = mass NaNO3 / molar mass NaNO3

moles NaNO3 = 2.00 g / 85.0 g/mol

moles NaNO3 = 0.0235 mol

Next, we need to calculate the total volume of the solution in liters, since concentration is usually expressed in moles per liter (M):

volume solution = 50.0 mL / 1000 mL/L

volume solution = 0.0500 L

Finally, we can use the moles of sodium nitrate and the total volume of the solution to calculate the concentration in moles per liter:

[NaNO3] = moles NaNO3 / volume solution

[NaNO3] = 0.0235 mol / 0.0500 L

[NaNO3] = 0.470 M

Therefore, the concentration of sodium nitrate in the solution is 0.470 M.