Question

What was the initial molarity of a sodium hydroxide solution if 45.0 mL of the solution was diluted such that the volume of the diluted sample is now 180 mL and the new concentration is 0.100 M NaOH?

___M (Answer Format X.X)

Answer 1

the sodium hydroxide solution was 0.4 M.

Step-by-step explanation:

To solve this problem, we can use the dilution formula:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

We are given that 45.0 mL of a sodium hydroxide solution was diluted and the resulting volume is 180 mL with a concentration of 0.100 M. Let's use M1 for the initial concentration, V1 for the initial volume, M2 for the final concentration, and V2 for the final volume.

M2 = 0.100 M

V1 = 45.0 mL

V2 = 180 mL

We can rearrange the dilution formula to solve for M1:

M1 = (M2V2) / V1

Substituting the given values, we get:

M1 = (0.100 M x 180 mL) / 45.0 mL

M1 = 0.400 M

Therefore, the initial molarity of the sodium hydroxide solution was 0.4 M.