Question

What volume was present before the dilution of a 1.00 M KOH solution if the new concentration is 0.250 M and the volume has increased to 450 mL?

___ mL (Answer Format XXX.X)

Answer 1

Answer: 112.5 mL

Step-by-step explanation:

We can use the dilution formula to determine the initial volume of the 1.00 M KOH solution:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Plugging in the given values, we get:

1.00 M x V1 = 0.250 M x 450 mL

Solving for V1, we get:

V1 = (0.250 M x 450 mL) / 1.00 M

V1 = 112.5 mL