Answer:
about -0.79 mg/hour
Explanation:
You want the rate of change of the amount of medication in a patient after 4 hours if the amount after t hours is modeled by y=88/(1+e^(t+0.7)).
Rate of change
The rate of change is found by taking the derivative of the function with respect to time. Let u = 1+e^(t+0.7). Then du/dt = e^(t +0.7).
The function can be written ...
y = 88/u = 88·u^-1
so its derivative is ...
dy/dt = (-88·u^-2)·du/dt
dy/dt = -88(e^(t +0.7))/(1 +e^(t +0.7))^2
At t=4
The value of the rate of change at t=4 is ...
dy/dt = -88(e^(4 +0.7))/(1 +e^(4 +0.7))^2 ≈ -88(109.95)/(1 +109.95)^2
dy/dt ≈ -0.78602 ≈ -0.79 . . . . . . mg/h
The rate of change in the amount of medication is about -0.79 mg/h.