When two inductors are connected in parallel, their equivalent inductance is given by:
1/L = 1/L1 + 1/L2
where L1 and L2 are the individual inductances.
Substituting the given values, we get:
1/L = 1/15 + 1/20
Simplifying and finding the common denominator, we get:
1/L = (4 + 3)/60
1/L = 7/60
Multiplying both sides by 60, we get:
L = 60/7 ≈ 8.57 H
Therefore, the total inductance of the circuit is approximately 8.57 H.