Question

Find an equation of the line whose intercepts are twice those of the graph of 5y+2x=10

Answer 1

`2x+5y=20`

Explanation:

Rearranging the equation of the given line into intercept form,

`5y+2x=10 \\ \\ (x)/(5)+(y)/(2)=1`

This means the intercepts are
`(5,0)` and
`(0,2)`.

We need to find the equation of the line with intercepts
`(0,4)` and
`(10,0)`. This equation is
`(x)/(10)+(y)/(4)=1`, which rearranges to give
`2x+5y=20`.