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The width of a rectangle is 4 units less than the length. The area of the rectangle is 32 square units. What is the width, in units, of the rectangle?

User CCCC
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2 Answers

5 votes

Answer:

the width of the rectangle is 4 units

Explanation:

Let's assume the length of the rectangle is "L" units.

According to the problem, the width of the rectangle is 4 units less than the length, which means the width is (L - 4) units.

The area of the rectangle is given as 32 square units, so we can write:

Length x Width = Area

L x (L - 4) = 32

Expanding the equation, we get:

L^2 - 4L = 32

Bringing all the terms to one side, we get:

L^2 - 4L - 32 = 0

Now, we can solve this quadratic equation for "L" using factoring or the quadratic formula. Factoring gives:

(L - 8)(L + 4) = 0

This gives two possible solutions for "L":

L = 8 or L = -4

We can reject the negative solution, since length cannot be negative. Therefore, the length of the rectangle is 8 units.

Using the equation for the width we found earlier, we can calculate the width of the rectangle as:

Width = L - 4 = 8 - 4 = 4 units.

User Alenros
by
8.6k points
3 votes

Answer:

4units

4 is 4 units less than 8 and 8 times 4 is 32

:)

User Nmfzone
by
8.1k points

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