Question

A survey of 240 families showed that

91 had a dog;
70 had a cat;
31 had a dog and a cat;
91 had neither a cat nor a dog, and in addition did not have a parakeet;
7 had a cat, a dog, and a parakeet.
How many had a parakeet only?

Answer 1

Explanation:

`n(p) only= \: n(p) - n(c n d np) \\ = 91 - 7 \\ = 84`

Answer 2

Ok

so the math that we need to do for this problem will be:

Total number of families = 240

minus the ones that don't have any pets = 91

minus the families that do have dogs = 91

minus the families that do have cats = 70

add back the overlap of dogs and cats = 31

add back the overlap of dogs cats parakeets = 7

240 - 91 - 91 - 70 + 31 + 7

^ this math will give us the families that ONLY have parakeets

so I stand by what I said before that this is the math you would to do get the answer to your problem

therefore its 26 buddy