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Dump Tower is 90 stories tall. A small, 1.5-kg object is dropped over the side of the roof of the tower and accelerates toward the ground. You will track the object for its entire fall. Each story of this tower is 3.85 meters tall.

What is the acceleration due to gravity of the planet and what is the impact speed of the object you dropped?
Time of fall 8.50sec.


30pts.
Thanks!

User Ed Chin
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1 Answer

4 votes

The distance the object falls is equal to the height of the building, which is 90 x 3.85 = 346.5 meters.

The acceleration due to gravity can be found using the equation:

d = 1/2 * g * t^2

where d is the distance the object falls, t is the time of fall, and g is the acceleration due to gravity.

Substituting the known values:

346.5 meters = 1/2 * g * (8.50 seconds)^2

Solving for g:

g = 2 * 346.5 meters / (8.50 seconds)^2

g = 9.74 m/s^2

So the acceleration due to gravity on the planet is 9.74 m/s^2.

The impact speed of the object can be found using the equation:

v = g * t

where v is the impact speed and t is the time of fall.

Substituting the known values:

v = 9.74 m/s^2 * 8.50 seconds

v = 82.8 m/s

So, the impact speed of the object is 82.8 m/s.

User Bruno Simoes
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