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A supply of NaOH is known to contain the contaminants NaCl and MgCl₂. A 4.955 g sample of this material is dissolved and diluted to 500.00 mL with water. A 20.00 mL sample of this solution is titrated with 22.26 mL of a 0.1989 M solution of HCI. What percentage of the original sample is NaOH? Assume that none of the contaminants react with HCI.​

User Mbiron
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1 Answer

2 votes

Answer:

88.55%

Step-by-step explanation:
4.9995 g of crude material contain 4.4275 g of NaOH, therefore

4.4275/4.9995 = 88.55%

User Climatebrad
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