Answer is D. ( 11, 0) and ( 3, 0)
Step by step
Given x^2 - 14x +33
To solve, use a table to find factors of 33.
There are only two: 33, 1 and 11, 3
Now we know one pair of numbers must multiply to equal 33 and also add to equal -14.
-11 x -3 = +33
-11 + -3 = -14
So the solution to the quadratic is
( x - 11 ) ( x - 3) = 0
Solve each
x - 11 = 0
Add 11 to each side to solve
x -11 + 11 = 0 + 11
Simplify
x = 11
x - 3 = 0
Add 3 to each side to solve
x -3 +3 = 0 + 3
Simplify
x = 3
So x = 11, x = 3
Y is 0 at x intercepts so
(11, 0) (3, 0) is your answer
I graphed it to prove the solution is correct
Your x coordinates are (-11,0) and (-3,0)