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What temperature in degree Celsius is needed to 3 change 2.5 dm³ of Nitrogen at 2 atm and 300 K to 3.0 dm³ and 2.5 atm? ​

User Gpbaculio
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2 Answers

5 votes

Final answer:

To change 2.5 dm³ of Nitrogen at 2 atm and 300 K to 3.0 dm³ and 2.5 atm, the temperature needed is 450 K, which is 177°C after converting from Kelvin.

Step-by-step explanation:

To find the temperature in degrees Celsius that is needed to change 2.5 dm³ of Nitrogen at 2 atm and 300 K to 3.0 dm³ and 2.5 atm, you can use the combined gas law, which is P1V1/T1 = P2V2/T2, where P is the pressure, V is the volume, and T is the temperature in Kelvin.

First, rearrange the equation to solve for T2:

T2 = (P2 * V2 * T1) / (P1 * V1)

Substitute the given values into the equation:

T2 = (2.5 atm * 3.0 dm³ * 300 K) / (2 atm * 2.5 dm³)

After calculating, you find:

T2 = 450 K

To convert this to degrees Celsius, subtract 273 from the Kelvin temperature:

T2°C = 450 K - 273 = 177°C

Therefore, 177°C is needed to change the conditions from the initial state to the final state.

User Andreasl
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4 votes

Answer:

the temperature needed to change 2.5 dm³ of nitrogen at 2 atm and 300 K to 3.0 dm³ and 2.5 atm is approximately 450 degrees Celsius.

Step-by-step explanation:

To solve this problem, we can use the combined gas law:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where P is pressure, V is volume, and T is temperature.

We are given:

P1 = 2 atm

V1 = 2.5 dm³

T1 = 300 K

And we are asked to find T2 when:

V2 = 3.0 dm³

P2 = 2.5 atm

Substituting these values into the combined gas law, we get:

(2 atm * 2.5 dm³) / (300 K) = (2.5 atm * 3.0 dm³) / (T2)

Simplifying this equation, we get:

T2 = (2.5 atm * 3.0 dm³ * 300 K) / (2 atm * 2.5 dm³)

T2 = 450 K

User Mesuti
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