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A piece of silver releases 113.8 Joules of heat while cooling 45.0 ° C. What is the mass of the sample? Silver has a specific heat of 0.240 J/g°C.

1 Answer

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We can use the formula for heat released:

Q = mcΔT

where Q is the heat released, m is the mass of the sample, c is the specific heat of the material, and ΔT is the change in temperature.

Plugging in the given values, we have:

113.8 J = m(0.240 J/g°C)(-45.0°C)

Simplifying:

m = 113.8 J / (0.240 J/g°C * -45.0°C)

m = 106.5 g

Therefore, the mass of the silver sample is 106.5 g.

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