Question

At time t = 0.00 s, a car is traveling along a straight line at a speed of 20 m/s with constant acceleration. The car travels 56.0 m during the time interval between t = 2.00 s and t = 4.00 s. What is the acceleration of the car?

Answer 1

We can solve this problem using the following kinematic equation: d = vit + 1/2at^2 where d is the displacement, vi is the initial velocity, a is the acceleration, and t is the time interval. We are given that the car is traveling at a speed of 20 m/s at t=0.00 s, so the initial velocity is vi = 20 m/s. We are also given that the car travels 56.0 m during the time interval between t=2.00 s and t=4.00 s, so the displacement is d = 56.0 m and the time interval is t = 2.00 s - 0.00 s = 2.00 s. Plugging these values into the equation, we get: 56.0 m = (20 m/s)(2.00 s) +