Question

A woman rolls a 8 kg bowling ball with an initial velocity of 10 m/s down a 20 meter tall hill. If the ball

rolls down the hill, then up a 5 meter tall hill, what is the velocity of the ball when it reaches the top of
the second hill?

Answer 1

The first step is to calculate the potential energy of the ball at the top of the first hill using the formula PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the hill. PE = (8 kg) x (9.8 m/s^2) x (20 m) = 1568 J Next, we can use the law of conservation of energy, which states that the total energy of a closed system remains constant. This means that the potential energy at the top of the first hill must be equal to the kinetic energy at the bottom of the hill, since there is no external work done on the ball. So, using the formula KE = 1/2mv^2, where v is the velocity of the ball, we can solve for v: KE = 1