Answer:
To calculate the amount of solute (NaNO3) that will be left after the saturated solution is evaporated to dryness, we need to use the solubility of NaNO3 in water at 30 degrees Celsius. The solubility of NaNO3 in water at 30 degrees Celsius is 88.0 g/100 mL. First, we need to convert the 50 grams of water to milliliters. The density of water at 30 degrees Celsius is 0.996 g/mL. Therefore: 50 g ÷ 0.996 g/mL = 50.2 mL So, we have 50.2 mL of water in which the solubility of NaNO3 is 88.0 g/100 mL. To calculate the amount of NaNO3 that will be left after the solution is evaporated to dryness, we can