Question

I need help with this ty

Answer 1

4 & 2

Step-by-step explanation:

If you plug in experimental values into the formula for kinetic energy, you will see the relationship.

1.

`(1)/(2)(2 kg)(2 m/s)^(2) = 4 kg * m^(2) /s^(2) \\\\(1)/(2)(8 kg)(2m/s)^(2) = 16 kg * m^(2) /s^(2)\\\\(16)/(4) = 4`

2.

`(1)/(2)(6 kg)(2m/s)^(2) = 12 kg * m^(2) /s^(2) \\\\(1)/(2)(3 kg)(2 m/s)^(2) = 6 kg * m^(2)/s^(2)\\ \\(12)/(6) = 2`