Question

A 0.45 kg stone is thrown at an initial velocity of 23.1 m/s [R 32o U]. Assuming the stone undergoes projectile motion, how much kinetic energy does it have at the top of its flight?

Answer 1

To solve this problem, we need to use the conservation of energy principle. At the top of its flight, the stone has zero kinetic energy and only potential energy due to its position above the ground. Therefore, we can calculate the potential energy and then use the conservation of energy to find the kinetic energy at the top of its flight. The gravitational potential energy of an object is given by the formula: PE = mgh where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the ground. The stone is thrown at an angle of 32 degrees above the horizontal, so its maximum height can be found using the formula: h = (v^2 * sin^2θ) / (2g) where v is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity