Question

Solve for x: p(x)=x^3+6x^2+3x-10=0

Answer 1

Explanation:

P(x)=x³+6x²+3x-10=0

x³+2x²+4x²+8x-5x-10=0

x²(x+2)+x(x+2)-5(x+2)=0

(x+2)(x²+x-5)=0

either x+2=0,x=-2

or

x²+x-5=0

`x=(-1 \pm √(1^2-4 * 1 *(-5)) )/(2 * 1) \\=(-1 \pm √(21) )/(2) \\Hence ~x=(-1+√(21) )/(2) \\or\\x=(-1 -√(21) )/(2)`