Step-by-step explanation:
(a) The genotype of the brown-eyed individual would be Bb, since they have a dominant B allele for brown eyes and a recessive b allele for blue eyes. The blue-eyed individual would have a genotype of bb.
(b) The offspring of the Bb x bb mating would have a 50% chance of inheriting the b allele from the Bb parent and a 50% chance of inheriting the b allele from the bb parent. Therefore, the expected proportions of the two eye colors among further offspring would be 50% brown-eyed and 50% blue-eyed.
(c) Each of the brown-eyed individuals who had one parent that was blue-eyed would be heterozygous Bb. Therefore, the expected proportions of the offspring's genotypes would be 25% BB, 50% Bb, and 25% bb. Since the B allele is dominant, the expected proportions of eye colors among their offspring would be 75% brown-eyed and 25% blue-eyed.