Answer:
Hopes this helps
Explanation:
Therefore , the solution of the given problem of triangle comes out to be the angle Y has a value of roughly 76.4 degrees.
What precisely is a triangle?
Because a triangle has four or more extra parts, it is a polygon. Its form is a straightforward rectangle. A triangle is a rectangle with the edges A, B, and C. A singular plane but instead cube are produced by Euclidean geometry when the sides aren't truly collinear. A triangular is a shape if it has three sides and three angles. Angles are the points where a quadrilateral three sides meet. A triangle's sides add up to 180 degrees.
Here,
We can determine the images of locations A, B, and C using the following method:
=> A': (-yA, xA)
=> B': (-yB, xB)
=> C": (-yC', xC')
where C' is the rotated version of location C.
We can determine the side lengths of triangular ABC using the Law of Cosines:
Assume that
=> a = BC = 2R sin(A/2) = 2R sin(45/2) 1.441R,
=> b = AC = 2R sin(B/2) = 2R sin(55/2) 1.663R, and
=> c = AB = 2R sin(C/2) = 2R sin(80/2) 2.219R.
where R represents the triangular ABC's circumradius.
Now, by turning point C 90 degrees anticlockwise with respect to the origin, we can determine the coordinates of point C':
xC' = -yC
yC' = xC
Then, to obtain the picture of point C, we can reflect point C' across the line y = x:
xC"=yC' and yC"=xC'
Again employing the Law of Cosines, we can determine the triangular XYZ's side lengths:
=> x = YZ = 2R sin(A'/2) = 2R sin(35) ≈ 1.189R
=> y = XZ = 2R sin(B'/2) = 2R sin(45) ≈ 1.414R
=> z = XY = 2R sin(C'/2) = 2R sin(55) ≈ 1.630R
where the picture angles of angles A, B, and C are A', B', and C', respectively.
Last but not least, we can apply the Law of Cosines once more to determine the size of angle Y:
cos(Y) i= t (x2 + z2 - y2)/ (2xz)
cos(Y) = 0.224 Y = 76.4 °
As a result, the angle Y has a value of roughly 76.4 degree