Answer:
40.8 m/s
Step-by-step explanation:
We can use the kinematic equation that relates the final velocity (Vf) of an object dropped from rest to the distance it has fallen (h) and the acceleration due to gravity (g):
Vf^2 = 2gh
where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.
Plugging in the given values, we get:
Vf^2 = 2 * 9.8 m/s^2 * 85 m
Vf^2 = 1666
Vf = sqrt(1666) ≈ 40.8 m/s
Therefore, the baseball will hit the ground with a speed of approximately 40.8 m/s.