Question

when the pressure of helium gas is increased to 4.1 atm, the volume is reduce to 1.2 l at a final temperature of 15 degrees celsius. what was the initial temperature of helium gas with a pressure of 3.5 atm and a volume 1.5 L?

Answer 1

Step-by-step explanation:

Re-arrange the equation to :

T1 = P1V1 * T2 / (P2V2) and note that temp needs to be in K

15C = 288.15 K

T1 = 3.5 (1.5)(288.15) /(4.1 * 1.2) = 307.48 K which is 34.3 C