Question

Which two values will make the equation true, for y ≠0

Answer 1

`y\sqrt[3]{6y}-14\sqrt[3]{48y}~~ = ~~-11y\sqrt[3]{6y} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \square y\sqrt[3]{6y}-14\sqrt[3]{48y^(\square )}\implies \square y\sqrt[3]{6y}-14\sqrt[3]{2^3\cdot 6y^(\square )}\implies \square y\sqrt[3]{6y}-28\sqrt[3]{6y^(\square )} \\\\\\ \underline{17} y\sqrt[3]{6y}-28\sqrt[3]{6y^{\underline{4}}}\implies 17y\sqrt[3]{6y}-28\sqrt[3]{6y^3\cdot y} \\\\\\ \stackrel{ \textit{like-terms} }{17y\sqrt[3]{6y}-28y\sqrt[3]{6y}}\implies \boxed{-11y\sqrt[3]{6y}}`