Question

Find X using Sine law

Answer 1

`\textit{Law of sines} \\\\ \cfrac{\sin(\measuredangle A)}{a}=\cfrac{\sin(\measuredangle B)}{b}=\cfrac{\sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\sin(x)}{32}=\cfrac{\sin(50^o)}{40}\implies \sin(x)=\cfrac{32\sin(50^o)}{40} \\\\\\ x=\sin^(-1)\left[ \cfrac{32\sin(50^o)}{40} \right]\implies x\approx 37.79^o`

Make sure your calculator is in Degree mode.