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How many moles exist in 390 g of silver nitrate ?

User Karl L
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2 Answers

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Answer:

there are approximately 2.3 moles of silver nitrate in 390 g.

Step-by-step explanation:

To find the number of moles in 390 g of silver nitrate, we first need to determine the molar mass of silver nitrate.

The molar mass of silver nitrate (AgNO3) is:

Ag: 107.87 g/mol

N: 14.01 g/mol

O (3): 15.99 g/mol x 3 = 47.97 g/mol

Total molar mass of AgNO3: 107.87 + 14.01 + 47.97 = 169.85 g/mol

Next, we can use the following formula to calculate the number of moles:

moles = mass (in grams) / molar mass

Plugging in the given values, we get:

moles = 390 g / 169.85 g/mol

moles = 2.296 mol (rounded to three significant figures)

Therefore, there are approximately 2.3 moles of silver nitrate in 390 g.

User SimpleButPerfect
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2 votes

Answer:

1 mole of silver nitrate has a mass = 169.87g

169.87g of silver nitrate corresponds to 1 mole of silver nitrate

Therefore 80.00g of silver nitrate corresponds to:

80.00g silver nitrate divided by 169.87g. = 0.4709 moles of silver nitrate

User RedXVII
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