Answer:
there are approximately 2.3 moles of silver nitrate in 390 g.
Step-by-step explanation:
To find the number of moles in 390 g of silver nitrate, we first need to determine the molar mass of silver nitrate.
The molar mass of silver nitrate (AgNO3) is:
Ag: 107.87 g/mol
N: 14.01 g/mol
O (3): 15.99 g/mol x 3 = 47.97 g/mol
Total molar mass of AgNO3: 107.87 + 14.01 + 47.97 = 169.85 g/mol
Next, we can use the following formula to calculate the number of moles:
moles = mass (in grams) / molar mass
Plugging in the given values, we get:
moles = 390 g / 169.85 g/mol
moles = 2.296 mol (rounded to three significant figures)
Therefore, there are approximately 2.3 moles of silver nitrate in 390 g.