Question

What volume of 0.550 M HCl can be prepared from 35.0 mL of 11.7 M HCl? Responses 1.13 mL 1.13 mL 18.4 mL 18.4 mL

Answer 1

To calculate the volume of 0.550 M HCl that can be prepared from 35.0 mL of 11.7 M HCl, we can use the following formula: M1V1 = M2V2 where M1 is the initial concentration of HCl (11.7 M), V1 is the initial volume of HCl (35.0 mL), M2 is the final concentration of HCl (0.550 M), and V2 is the final volume of HCl that we need to calculate. Rearranging the formula to solve for V2, we get: V2 = (M1V1) / M2 Substituting the given values, we get: V2 = (11.7 M)(35.0 mL) / 0.550 M V2 = 747.27 mL Therefore,