Question

A town is designing a rectangular park that will be 600 feet wide by 1000 feet long. On a scale drawing, the dimensions of the park are 12 inches wide by 20 inches long. A rectangular area of the park for swing sets is 0.5 inch wide by 2 inches long on the scale drawing.

What is the actual length of the swing set area of the park?

Enter your answer in the box.

The actual length of the swing set area of the park is ______ feet.

Answer 1

The dimensions of the park on the scale drawing is 12 inches and 20 inches.

Dimension

Actual dimensions:

Park = 600 feet by 1000 feet

Swing set = 25 feet by 100 feet

Swing set on the scale drawing= 0.5 inch by 2 inches

Hence:

Dimension of park on drawing:

Width = 600×1/50

Width = 12inches

Length = 1000×1/50

Length= 20inches

Inconclusion the dimensions of the park on the scale drawing is 12 inches and 20 inches.

Answer 2

Answer: The actual length of the swing set area of the park is 25 ft long and 100 ft wide.

For a particular scale drawing, it is already specified that all the measurements' some constant scaled version will be taken. For example, let the scale be K feet to s inches.

Then it means

All feet measurements will then be multiplied by s/k to get the drawing's corresponding lengths.

For the given case, it is given that Real dimension of a rectangular park: 600 ft by 1000 ft In drawing, it was of 12 inches by 20 inches. Let the scale that the drawing is using be k feet to s inches, then.

Since it is given that 600 ft: 12 inches and 1000 ft: 20 inches, thus, we get: Thus, every foot is reduced 0.02 times in drawing.

Now, it is given that in drawing, the rectangular area for swing sets is 0.5 inch to 2 inch. Let its real length was L and real width was W. Then we have:

Since these are only magnitudes, and unit was converted from feet to inches, so we have L = 25 feet and W = 100 feet

Thus, the actual length of the swing set area of the park is 25 ft long and 100 ft wide