190k views
4 votes
Please help me solve this

Please help me solve this-example-1

1 Answer

3 votes

Explanation:

what "normal" trigonometric function did this remind us of ?

it starts at "high" for x = 0.

"high" signs mean "1" for the standard functions.

the trigonometric function that starts with 1 at x = 0 is cosine.

so, this is a cosine function that we need to scale properly.

original value : 1

graph : 15

original value : -1

graph : 12

original value : 0

graph : (15+12)/2 = 27/2 = 13.5

so, we need to add this to the cosine function result.

the distance from the 0 level (13.5) to high or low is 1.5 (instead of originally 1).

Du, we need to stretch the cosine function result to go from -1.5 to +1.5 (12 to 15).

and for the x-axis :

12 hours = 180° or pi (the interval for cosine to go from +1 to -1).

1 hour = 180/12 = 15° or pi/12.

so, for cosine to react to the hour value as for the curdling degrees we need to multiply x by 180/12 or by pi/12.

so, our temperature function temp(x) is then

temp(x) = 1.5×cos(x×180/12) + 13.5

or

temp(x) = 1.5×cos(x×pi/12) + 13.5

User Nuby
by
8.5k points