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What is the minimum value of f(x) = x^2 + 6x + 4

User SlimJim
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1 Answer

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Answer:

-5

Explanation:

You want the minimum value of f(x) = x² +6x +4.

Line of symmetry

The line of symmetry of a quadratic function f(x) = ax² +bx +c is given by ...

x = -b/(2a)

The line of symmetry passes through the extreme point. When a > 0, that extreme point is the minimum.

Here, we have a=1, b=6, so the line of symmetry is ...

x = -6/(2·1) = -3

Extreme

The extreme point (minimum) is ...

f(-3) = (-3)² +6(-3) +4 = (-3 +6)(-3) +4 = -9 +4

f(-3) = -5

The minimum value of f(x) is -5.

What is the minimum value of f(x) = x^2 + 6x + 4-example-1
User Lashan Fernando
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