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Find the probability of exactly 5 successes in 7 trials of a binomial experiment in which the probability of success is 70%

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\blue{\huge {\mathrm{PROBABILITY}}}


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{\underline{\huge \mathbb{Q}{\large \mathrm {UESTION : }}}}

  • Find the probability of exactly 5 successes in 7 trials of a binomial experiment in which the probability of success is 70%.


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{\underline{\huge \mathbb{A} {\large \mathrm {NSWER : }}}}

  • The probability of exactly 5 successes in 7 trials of a binomial experiment in which the probability of success is 70% is 0.3176523.


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{\underline{\huge \mathbb{S} {\large \mathrm {OLUTION : }}}}

We can use the binomial probability formula to find the probability of exactly 5 successes in 7 trials:


\sf P(5\: successes\: in\: 7\: trials) = (7\: choose\: 5) (0.7)^5 (0.3)^2

where:

  • n = 7 (number of trials),
  • p = 0.7 (probability of success),
  • q = 0.3 (probability of failure), and
  • (7 choose 5) = 7!/(5!2!) = 21 (the number of ways to choose 5 successes in 7 trials).

Plugging in these values, we get:


\begin{aligned}\sf P(5\: successes\: in\: 7\: trials)& =\sf 21 (0.7)^5 (0.3)^2\\& =\bold{ 0.3176523}\end{aligned}

Therefore, the probability of exactly 5 successes in 7 trials of a binomial experiment in which the probability of success is 70% is 0.3176523.


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User Minaz
by
7.4k points
2 votes

Answer:

0.3176523

Explanation:

You want the probability of exactly 5 successes in 7 trials of a binomial experiment in which the probability of success is 70%.

Probability

The desired probability is the product of the probability of 5 success and 2 failures, multiplied by the number of ways that result might occur.

P(x=5) = 7C5·(0.7^5)(1 -0.7)^2 = 0.3176523

The probability of exactly 5 successes is 0.3176523.

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Additional comment

Any of a number of probability calculators can tell you this probability. Spreadsheets have appropriate functions built in as well.

Find the probability of exactly 5 successes in 7 trials of a binomial experiment in-example-1
User Milos Cuculovic
by
7.9k points