Answer:
The vertex of the quadratic function f(x) = -2x^2 + 8x is (2, 8).
Explanation:
To find the vertex of the quadratic function f(x) = -2x^2 + 8x, we first need to find the x-coordinate of the vertex using the formula:
x = -b / 2a
where a = -2 and b = 8. Substituting these values, we get:
x = -8 / 2(-2) = 2
Now, to find the y-coordinate of the vertex, we can substitute this value of x back into the equation: f(2) = -2(2)^2 + 8(2) = 8