Answer:
The volume of the gas at a pressure of 15.33 psi is 3.28 liters.
Step-by-step explanation:
To solve this problem, we need to use the combined gas law, which relates the pressure, volume, and temperature of a gas:P1V1/T1 = P2V2/T2where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.We can rearrange this equation to solve for V2:V2 = (P1V1T2)/(P2T1)Let's plug in the values given in the problem:P1 = 1.00 atm
V1 = 3.60 L
T1 = 25.0 C + 273.15 = 298.15 K
P2 = 15.33 psi
T2 = 25.0 C + 273.15 = 298.15 KWe need to convert the pressure to the same units as P1, which is atm:1 psi = 0.068046 atm
15.33 psi = 15.33 x 0.068046 atm = 1.044 atmNow we can calculate V2:V2 = (P1V1T2)/(P2T1)
V2 = (1.00 atm x 3.60 L x 298.15 K)/(1.044 atm x 298.15 K)
V2 = 3.28 L