Question

Three ballet dancers are positioned on stage. Max is 2 feet straight behind Kenji and 4 feet directly left of Lindsey. When the music begins, Max twirls to Lindsey's position, then leaps to Kenji's position, and finally walks back to his original position. How far did Max travel? If necessary, round to the nearest tenth.

Answer 1

The distance Max traveled can be found by calculating the distance of each movement he makes and adding them up. First, we need to use the Pythagorean theorem to calculate the distance between Lindsey and Max:

sqrt(4^2 + 2^2) = sqrt(16 + 4) = sqrt(20) = 2*sqrt(5)

So, Max travels 2*sqrt(5) feet to get to Lindsey's position. Next, he travels the distance between Kenji and Lindsey, which is 4 feet:

distance = 4

Finally, he travels in a straight line back to his original position, which is 2 feet straight behind Kenji:

distance = 2

Adding these distances together, we get:

2*sqrt(5) + 4 + 2 = 2*sqrt(5) + 6

Rounding to the nearest tenth gives us a final answer of approximately 8.5 feet.

Answer 2

Answer: 8.5 feet

Explanation:

To determine how far Max traveled, we can use the Pythagorean theorem to find the distances between the points.

Max twirls to Lindsey's position:

Since Max is 2 feet behind Kenji and 4 feet left of Lindsey, Max and Lindsey form a right triangle with legs of 2 feet and 4 feet. Using the Pythagorean theorem:

a² + b² = c²

2² + 4² = c²

4 + 16 = c²

20 = c²

Taking the square root of both sides:

c = √20 ≈ 4.47 feet (rounded to the nearest tenth)

Max leaps to Kenji's position:

Since Max was initially 2 feet behind Kenji, the distance between Lindsey and Kenji is also 2 feet.

Max walks back to his original position:

The distance between Max's original position and Kenji's position is 2 feet.

Adding up the distances:

4.47 feet (Max to Lindsey) + 2 feet (Lindsey to Kenji) + 2 feet (Kenji to Max's original position) = 8.47 feet

So, Max traveled approximately 8.5 feet (rounded to the nearest tenth) during his movements.