Question

2. A professional bowler is bowling. She is able to bowl a strike 83% of the time. If she

bowls 10 times, what is the probability she gets exactly 6 strikes?

Answer 1

The probability of the professional bowler getting exactly 6 strikes out of 10 attempts is approximately 0.296, or 29.6%.

Explanation:

This is an example of a binomial distribution, where we have a fixed number of independent trials (bowling 10 times), each with a fixed probability of success (bowling a strike, which has a probability of 0.83).To find the probability of getting exactly 6 strikes, we can use the binomial probability formula:P(X = k) = (n choose k) * p^k * (1-p)^(n-k)

where:

n is the number of trials (bowling 10 times)

k is the number of successes (getting exactly 6 strikes)

p is the probability of success on each trial (0.83)

(n choose k) is the binomial coefficient, which can be calculated as n! / (k! * (n-k)!)

Plugging in the values, we get:P(X = 6) = (10 choose 6) * 0.83^6 *

(1-0.83)^(10-6)

= (10! / (6! * 4!)) * 0.83^6 * 0.17^4

= 0.296

Answer 2

The probability of the professional bowler getting exactly 6 strikes out of 10 times bowling is approximately 0.2968 or 29.68%.