Question

If x^2 + y^2 = m and xy = n, find the value of 16m + 32n

Answer 1

(4x+4y)²

Explanation:

Given x²+y² = m ,xy=n.

Now 16m+32n = 16(m+2n)

= 16(x²+y²+2xy) = 4²(x+y)²[ x²+y²+2xy= (x+y)²]

(4x+4y)².