First, we write the polynomial in descending order of degree:
4x³+7x²-8x-14
Now, we start dividing the first term of the dividend by the divisor:
x²
___________
4x+7|4x³+7x²-8x-14
We multiply x² by 4x+7 to get:
x²
___________
4x+7|4x³+7x²-8x-14
4x³+7x²
-8x
Now we bring down the next term:
x²-2
___________
4x+7|4x³+7x²-8x-14
4x³+7x²
-8x-14
+8x+14
_______
0
The remainder is zero, which means that 4x+7 is a factor of 4x³+7x²-8x-14. The quotient is x²-2.
Therefore, the result when 4x³+7x²-8x-14 is divided by 4x+7 is:
4x³+7x²-8x-14 = (4x+7)(x²-2) + 0
So, the quotient is x²-2, and there is no remainder.