Answer:
The axis of symmetry is at x = -2.
Explanation:
To find the axis of symmetry of a quadratic function in the form of f(x) = ax^2 + bx + c, you can use the formula x = -b / (2a).
In the function f(x) = 2x^2 + 8x − 5, a = 2 and b = 8, so we can plug those values into the formula and get:
x = -b / (2a) = -8 / (2 * 2) = -2
Therefore, the axis of symmetry of the function f(x) = 2x^2 + 8x − 5 is located at x = -2.
This means that the graph of the function is symmetric with respect to the vertical line x = -2. Any point on the graph that is a distance of t from the line x = -2 will have a corresponding point on the graph that is also a distance of t from the line.