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The point ( 2, √—

5 ) lies on the circle centered at the

origin with radius 3.

1 Answer

4 votes

To check whether the point (2, √5) lies on the circle centered at the origin with radius 3, we can use the distance formula for a point (x, y) on the circle:

d = √((x - 0)^2 + (y - 0)^2)

Since the center of the circle is at the origin, the x-coordinate is 0 and the y-coordinate is 0. The radius is given as 3. So, substituting these values in the above formula, we get:

3 = √((2 - 0)^2 + (√5 - 0)^2)

Simplifying the right side of the equation:

3 = √(4 + 5)

3 = √9

3 = 3

Since both sides of the equation are equal, the point (2, √5) lies on the circle centered at the origin with radius 3.

User Mark Edington
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