Question

PLEASE HELP!!!!

Question: Write the equation of a line parallel to y = x -5 that goes through (7,0).

Answer 1

To find the equation of a line parallel to y = x - 5 that goes through (7,0), we need to use the fact that parallel lines have the same slope.

The slope of the line y = x - 5 is 1, since the coefficient of x is 1. Therefore, the slope of the parallel line we want to find is also 1.

Using the point-slope form of a line, we can write the equation of the parallel line as:

y - y1 = m(x - x1)

where (x1, y1) is the point (7,0) and m is the slope of the line, which we know is 1.

Plugging in the values, we get:

y - 0 = 1(x - 7)

Simplifying, we get:

y = x - 7

Therefore, the equation of the line parallel to y = x - 5 that goes through (7,0) is y = x - 7.

Answer 2

y = x - 7

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x - 5 ← is in slope- intercept form

with slope m = 1

• Parallel lines have equal slopes , then

y = x + c ← is the partial equation

to find c substitute (7, 0 ) into the partial equation

0 = 7 + c ( subtract 7 from both sides )

- 7 = c

y = x - 7 ← equation of parallel line