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5 votes
41st term of 12,19,26

2 Answers

6 votes
The answer is 292 pls give me brain dead
User Wal
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Answer:

292

Explanation:

To find the 41st term of the sequence 12, 19, 26, we need to first find the common difference, d, between consecutive terms. We can do this by subtracting the first term from the second term (or the second term from the third term). So the common difference is 7. Now we can use the formula for the nth term of an arithmetic sequence. where an is the nth term, a1 is the first term, d is the common difference, and n is the term we want to find. Substituting the given values, you get the 41st sequence is 292.

User Soorapadman
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