Answer: Since cos(theta) = 2/3 and theta is in quadrant IV, we know that sin(theta) is negative. We can use the Pythagorean identity to find the value of sin(theta):
sin^2(theta) + cos^2(theta) = 1
Substituting cos(theta) = 2/3, we get:
sin^2(theta) + (2/3)^2 = 1
Simplifying, we get:
sin^2(theta) = 1 - (2/3)^2 = 1 - 4/9 = 5/9
Since sin(theta) is negative in quadrant IV, we have:
sin(theta) = -sqrt(5/9) = -sqrt(5)/3
Therefore, sin(theta) = -sqrt(5)/3.
Explanation: